document.write( "Question 195938: 2(sqrt of 3 + sqrt of 12) \n" ); document.write( "
Algebra.Com's Answer #146912 by jim_thompson5910(35256)\"\" \"About 
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\"2%28sqrt%283%29%2Bsqrt%2812%29%29\" Start with the given expression.\r
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\n" ); document.write( "\n" ); document.write( "\"2%2Asqrt%283%29%2B2%2Asqrt%2812%29\" Distribute\r
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\n" ); document.write( "\n" ); document.write( "\"2%2Asqrt%283%29%2B2%2Asqrt%284%2A3%29\" Factor\r
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\n" ); document.write( "\n" ); document.write( "\"2%2Asqrt%283%29%2B2%2Asqrt%284%29%2Asqrt%283%29\" Break up the square root\r
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\n" ); document.write( "\n" ); document.write( "\"2%2Asqrt%283%29%2B2%2A2%2Asqrt%283%29\" Take the square root of 4 to get 2\r
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\n" ); document.write( "\n" ); document.write( "\"2%2Asqrt%283%29%2B4%2Asqrt%283%29\" Multiply\r
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\n" ); document.write( "\n" ); document.write( "\"6%2Asqrt%283%29\" Combine like terms.\r
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\n" ); document.write( "\n" ); document.write( "So \"2%28sqrt%283%29%2Bsqrt%2812%29%29=6%2Asqrt%283%29\"
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