document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=195908>Question 195908</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How can you solve 6^x+2=3^x+1 with out the calculator? I think you really can't because I tried it with the calculator and x comes out to be -3.584... so then the exponent would be a negative number...so I can't use logs. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #146895 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=146895\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 6^(x+2) = 3^(x+1)<BR>\n" );
document.write( "(x+2)log6 = (x+1)log3<BR>\n" );
document.write( "---<BR>\n" );
document.write( "[log(6)-log(3)]x = [log(3) - 2log(6)]<BR>\n" );
document.write( "---<BR>\n" );
document.write( "x =  [log(3) - 2log(6)] / [log(6)-log(3)]\r<BR>\n" );
document.write( "\n" );
document.write( "x = log(3/6^2) / log(2)\r<BR>\n" );
document.write( "\n" );
document.write( "---<BR>\n" );
document.write( "x = log(1/12)/log(2)<BR>\n" );
document.write( "x = log(base 2) (1/12)<BR>\n" );
document.write( "=================================<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );