document.write( "Question 195864: sqrt(3x+10)=5-2x
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document.write( "solve for x
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document.write( "answer key says 3/4\r
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document.write( "my work
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document.write( "sqrt(3x+10)=5-2x
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document.write( "sqrt(3x+10)^2=(5-2x)^2
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document.write( "3x+10=25-4x
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document.write( "3x+4x+10=25-4x+4x
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document.write( "7x+10=25
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document.write( "7x+10-10=25-10
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document.write( "7x=15
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document.write( "7x/7=15/7
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document.write( "x=15/7 \n" );
document.write( "
Algebra.Com's Answer #146885 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! sqrt(3x+10)=5-2x SQUARE BOTH SIDES. \n" ); document.write( "[sqrt(3x+10)]^2=(5-2x)^2 \n" ); document.write( "3x+10=(25-20x+4X^2} \n" ); document.write( "3x+10=25-20x+4X^2 COMBINE LIKE TERMS. \n" ); document.write( "-4X^2+23x+10-25=0 MULTIPLY BY -1. \n" ); document.write( "4X^2-23x+15=0 \n" ); document.write( "(4X-3)(X-5)=0 \n" ); document.write( "4X-3=0 \n" ); document.write( "4X=3 \n" ); document.write( "X=3/4 ANS. \n" ); document.write( "X-5=0 \n" ); document.write( "X=5 ANS. \n" ); document.write( " |