document.write( "Question 195889: Calvin invested $7500 for one year, part at 12% annual interest and the rest at 10% annual interest. his total interest fot the year was $890. How much money did he invest at 12%? \n" ); document.write( "
Algebra.Com's Answer #146881 by checkley77(12844) ![]() You can put this solution on YOUR website! .12x+.10(7,500-x)=890 \n" ); document.write( ".12x+750-.10x=890 \n" ); document.write( ".02x=890-750 \n" ); document.write( ".02x=140 \n" ); document.write( "x=140/.02 \n" ); document.write( "x=$7,000 is the amount invested @ 12%. \n" ); document.write( " |