document.write( "Question 195889: Calvin invested $7500 for one year, part at 12% annual interest and the rest at 10% annual interest. his total interest fot the year was $890. How much money did he invest at 12%? \n" ); document.write( "
Algebra.Com's Answer #146881 by checkley77(12844)\"\" \"About 
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.12x+.10(7,500-x)=890
\n" ); document.write( ".12x+750-.10x=890
\n" ); document.write( ".02x=890-750
\n" ); document.write( ".02x=140
\n" ); document.write( "x=140/.02
\n" ); document.write( "x=$7,000 is the amount invested @ 12%.
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