document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=195832>Question 195832</A>: <I><SPAN STYLE=\"word-break: break-all;\"> find the mean of the 15 th through 55 th terms inclusive of the sequence:\r<BR>\n" );
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document.write( "a billow n = 7 - 4n please i need help to solve any one please help..... </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #146853 by </B><A HREF=/tutors/aboutme.mpl?userid=RAY100><B>RAY100(1637)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=RAY100><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=146853\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> a(n) = 7-4n<BR>\n" );
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document.write( "The  form  is  that  of  an  arithmetic  series,  a(n) = a(1) +(n-1)d<BR>\n" );
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document.write( "a(15) = 7-4(15) = -53<BR>\n" );
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document.write( "a(55) = 7-4(55) = -213<BR>\n" );
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document.write( "Mean  is  average  in  arithmetic  series<BR>\n" );
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document.write( "mean  = - (213 +53) /2 = -133 </SPAN>\n" );
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