document.write( "Question 26966: I need help with the following problem please.
\n" ); document.write( "A car is taking a trip driving to James Town that is 80 miles away. On the return trip the car is driving 10 miles/hour slower on the way back. It took 20 minutes longer to get back . How fast was the car traveling on the trip to James Town and how fast was it traveling on the return trip.\r
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Algebra.Com's Answer #14678 by Paul(988)\"\" \"About 
You can put this solution on YOUR website!
On going he ws travelling at x mph
\n" ); document.write( "On way back he was travelling at x-10mph.
\n" ); document.write( "Total distance = 80
\n" ); document.write( "20 minutes = 1/3h\r
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\n" ); document.write( "\n" ); document.write( "\"80%2Fx%2B80%2F%28x-10%29=1%2F3\"
\n" ); document.write( "\"80%28%28x%29-%28x-10%29%29=1%28x%29%28x-10%29%2F3\"
\n" ); document.write( "\"800=%28x%5E2-10x%29%2F3\"
\n" ); document.write( "\"2400=x%5E2-10x\"
\n" ); document.write( "\"x%5E2-10x-2400=0\"
\n" ); document.write( "Use quadratic formula and solve you get
\n" ); document.write( "\"x=5sqrt%2897%2B1%29\"
\n" ); document.write( "x=54.2 (rounded)\r
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\n" ); document.write( "\n" ); document.write( "54.2-10=44.2\r
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\n" ); document.write( "\n" ); document.write( "Hence, he speed going was 54.2mph and his speed returning was 44.2mph.
\n" ); document.write( "Paul.
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