document.write( "Question 195733: Building a pool in the shape of an ellipse. The equation for the pool is x^2/324 + y^2/196 = 1 Find the longest distance and shortest distance across the pool.
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document.write( "I'm not sure where to start?
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document.write( "y^2=1-x^2/324 and then square both sides? \n" );
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Algebra.Com's Answer #146778 by jim_thompson5910(35256)![]() ![]() ![]() You can put this solution on YOUR website! \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So the equation is now in the form \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The longest distance between any two points along a line on the ellipse falls on the major axis. The length of the semi major axis simply turns out to be the larger value of \"a\" or \"b\"\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Since \"a\" is larger, this means that the length of the semi major axis is 18 units. Double this value to get 36 units.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So the the longest distance across the pool is 36 units.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "For the shortest distance, just use the smaller value 14 and double it to 28. \r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So the the shortest distance across the pool is 28 units. \n" ); document.write( " |