document.write( "Question 195733: Building a pool in the shape of an ellipse. The equation for the pool is x^2/324 + y^2/196 = 1 Find the longest distance and shortest distance across the pool.
\n" ); document.write( "I'm not sure where to start?
\n" ); document.write( "y^2=1-x^2/324 and then square both sides?
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Algebra.Com's Answer #146778 by jim_thompson5910(35256)\"\" \"About 
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\"x%5E2%2F324+%2B+y%5E2%2F196+=+1+\" Start with the given equation.\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2%2F18%5E2+%2B+y%5E2%2F196+=+1+\" Rewrite \"324\" as \"18%5E2\"\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2%2F18%5E2+%2B+y%5E2%2F14%5E2+=+1+\" Rewrite \"196\" as \"14%5E2\"\r
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\n" ); document.write( "\n" ); document.write( "So the equation is now in the form \"%28x-h%29%5E2%2Fa%5E2%2B%28y-k%29%5E2%2Fb%5E2=1\" (which is the general equation of an ellipse) where \"h=0\", \"k=0\", \"a=18\" and \"b=14\"\r
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\n" ); document.write( "\n" ); document.write( "The longest distance between any two points along a line on the ellipse falls on the major axis. The length of the semi major axis simply turns out to be the larger value of \"a\" or \"b\"\r
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\n" ); document.write( "\n" ); document.write( "Since \"a\" is larger, this means that the length of the semi major axis is 18 units. Double this value to get 36 units.\r
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\n" ); document.write( "\n" ); document.write( "So the the longest distance across the pool is 36 units.\r
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\n" ); document.write( "\n" ); document.write( "For the shortest distance, just use the smaller value 14 and double it to 28. \r
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\n" ); document.write( "\n" ); document.write( "So the the shortest distance across the pool is 28 units.
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