document.write( "Question 195713: Hello,
\n" ); document.write( "Not sure if I chose the right catorgory but I need help with the following problem.\r
\n" ); document.write( "\n" ); document.write( "The area of a rectangle is 55 square meters. Find the length and width of the rectangle if its length is 6 meters greater than its width. Use an equation and the formula for area of a rectangle A = l × w \r
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Algebra.Com's Answer #146769 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
First, we'll use the area of a rectangle formula \"A=LW\". Also, since \"its length is 6 meters greater than its width\", this means that \"L=W%2B6\"\r
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\n" ); document.write( "\n" ); document.write( "\"A=LW\" Start with the given equation.\r
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\n" ); document.write( "\n" ); document.write( "\"55=%28W%2B6%29W\" Plug in \"L=W%2B6\"\r
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\n" ); document.write( "\n" ); document.write( "\"55=W%28W%2B6%29\" Rearrange the terms.\r
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\n" ); document.write( "\n" ); document.write( "\"55=W%5E2%2B6W\" Distribute\r
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\n" ); document.write( "\n" ); document.write( "\"0=W%5E2%2B6W-55\" Subtract 55 from both sides.\r
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\n" ); document.write( "\n" ); document.write( "Notice we have a quadratic equation in the form of \"0=aW%5E2%2BbW%2Bc\" where \"a=1\", \"b=6\", and \"c=-55\"\r
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\n" ); document.write( "\n" ); document.write( "Let's use the quadratic formula to solve for W\r
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\n" ); document.write( "\n" ); document.write( "\"W+=+%28-b+%2B-+sqrt%28+b%5E2-4ac+%29%29%2F%282a%29\" Start with the quadratic formula\r
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\n" ); document.write( "\n" ); document.write( "\"W+=+%28-%286%29+%2B-+sqrt%28+%286%29%5E2-4%281%29%28-55%29+%29%29%2F%282%281%29%29\" Plug in \"a=1\", \"b=6\", and \"c=-55\"\r
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\n" ); document.write( "\n" ); document.write( "\"W+=+%28-6+%2B-+sqrt%28+36-4%281%29%28-55%29+%29%29%2F%282%281%29%29\" Square \"6\" to get \"36\". \r
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\n" ); document.write( "\n" ); document.write( "\"W+=+%28-6+%2B-+sqrt%28+36--220+%29%29%2F%282%281%29%29\" Multiply \"4%281%29%28-55%29\" to get \"-220\"\r
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\n" ); document.write( "\n" ); document.write( "\"W+=+%28-6+%2B-+sqrt%28+36%2B220+%29%29%2F%282%281%29%29\" Rewrite \"sqrt%2836--220%29\" as \"sqrt%2836%2B220%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"W+=+%28-6+%2B-+sqrt%28+256+%29%29%2F%282%281%29%29\" Add \"36\" to \"220\" to get \"256\"\r
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\n" ); document.write( "\n" ); document.write( "\"W+=+%28-6+%2B-+sqrt%28+256+%29%29%2F%282%29\" Multiply \"2\" and \"1\" to get \"2\". \r
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\n" ); document.write( "\n" ); document.write( "\"W+=+%28-6+%2B-+16%29%2F%282%29\" Take the square root of \"256\" to get \"16\". \r
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\n" ); document.write( "\n" ); document.write( "\"W+=+%28-6+%2B+16%29%2F%282%29\" or \"W+=+%28-6+-+16%29%2F%282%29\" Break up the expression. \r
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\n" ); document.write( "\n" ); document.write( "\"W+=+%2810%29%2F%282%29\" or \"W+=++%28-22%29%2F%282%29\" Combine like terms. \r
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\n" ); document.write( "\n" ); document.write( "\"W+=+5\" or \"W+=+-11\" Simplify. \r
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\n" ); document.write( "\n" ); document.write( "So the possible answers are \"W+=+5\" or \"W+=+-11\"\r
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\n" ); document.write( "\n" ); document.write( "However, a negative width doesn't make much sense. So this means we'll ignore \"W+=+-11\"\r
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\n" ); document.write( "\n" ); document.write( "So the solution is \"W+=+5\" which makes the width 5 meters.\r
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\n" ); document.write( "\n" ); document.write( "\"L=W%2B6\" Go back to the second equation\r
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\n" ); document.write( "\"L=5%2B6\" Plug in \"z+=+5\"\r
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\n" ); document.write( "\n" ); document.write( "\"L=11\" Add\r
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\n" ); document.write( "\n" ); document.write( "So the length is 11 meters.
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