document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=26962>Question 26962</A>: <I><SPAN STYLE=\"word-break: break-all;\"> how do u solve this by using substitution<BR>\n" );
document.write( "x+2y=6<BR>\n" );
document.write( "x-3y=-4 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #14676 by </B><A HREF=/tutors/aboutme.mpl?userid=elima><B>elima(1433)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=elima><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=14676\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> First lets take the second equation and solve for x;<BR>\n" );
document.write( "x-3y=-4<BR>\n" );
document.write( "x=-4+3y<BR>\n" );
document.write( "Now substitute that for x in equation 1;<BR>\n" );
document.write( "(-4+3y)+2y=6<BR>\n" );
document.write( "-4+5y=6<BR>\n" );
document.write( "5y=6+4<BR>\n" );
document.write( "5y=10<BR>\n" );
document.write( "y=2<BR>\n" );
document.write( "Now we have what y =, lets plug that into the equation and solve for x;<BR>\n" );
document.write( "x-3(2)=-4<BR>\n" );
document.write( "x-6=-4<BR>\n" );
document.write( "x=-4+6<BR>\n" );
document.write( "x=2<BR>\n" );
document.write( "Hope you understand<BR>\n" );
document.write( "=) </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );