document.write( "Question 195696This question is from textbook
\n" ); document.write( ": A B747 aircraft flew 6 hours with the wind. The return trip took 7 hours against the wind. If the speed of the plane in still air is 13 times the speed of the wind, find the wind speed and the speed of the plane in still air. \n" ); document.write( "
Algebra.Com's Answer #146752 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
A B747 aircraft flew 6 hours with the wind. The return trip took 7 hours
\n" ); document.write( " against the wind. If the speed of the plane in still air is 13 times the
\n" ); document.write( " speed of the wind, find the wind speed and the speed of the plane in still air.
\n" ); document.write( ":
\n" ); document.write( "Let x = speed of the wind
\n" ); document.write( "then
\n" ); document.write( "13x = speed of the plane in still air
\n" ); document.write( "then
\n" ); document.write( "12x = speed against the wind
\n" ); document.write( "and
\n" ); document.write( "14x = speed with the wind
\n" ); document.write( ":
\n" ); document.write( "Distance of the trips are equal so write a dist equation: dist = time * speed
\n" ); document.write( ":
\n" ); document.write( "7(12x) = 6(14x)
\n" ); document.write( "84x = 84x like you would expect, just pick a speed for wind
\n" ); document.write( "Say 40 mph
\n" ); document.write( "then
\n" ); document.write( "13*40 = 520 mph is the plane in still air, sounds reasonable, other speeds will work too
\n" ); document.write( "
\n" ); document.write( "
\n" );