document.write( "Question 195688: The owner of a sidewalk expresso stand find that the weekly profit for their business is a function of the price they charge per cup. If x equals the price(in dollars) of one cup, the weekly profit is given P(x)= -2900x^2 + 7250 - 2900.\r
\n" ); document.write( "\n" ); document.write( "Approximate the maximum profit and the price per cup that produces that profit.
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Algebra.Com's Answer #146750 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
\"P%28x%29=+-2900x%5E2+%2B+7250x+-+2900\"
\n" ); document.write( "When the equation is in the form
\n" ); document.write( "\"ax%5E2+%2B+bx+%2B+c\", the max or min
\n" ); document.write( "of the function occurs at:
\n" ); document.write( "\"x%5Bmax%5D+=+-b%2F%282a%29\" (max in this case)
\n" ); document.write( "\"x%5Bmax%5D+=+-7250+%2F+%282%2A%28-2900%29%29\"
\n" ); document.write( "\"x%5Bmax%5D+=+7250+%2F+5800\"
\n" ); document.write( "\"x%5Bmax%5D+=+1.25\"
\n" ); document.write( "At maximum profit, the price per cup is $1.25
\n" ); document.write( "And to find the maximum profit:
\n" ); document.write( "\"P%28x%29=+-2900x%5E2+%2B+7250x+-+2900\"
\n" ); document.write( "\"P%281.25%29=+-2900%2A1.25%5E2+%2B+7250%2A1.25+-+2900\"
\n" ); document.write( "\"P%281.25%29=+-4531.25+%2B+9062.5+-+2900\"
\n" ); document.write( "\"P%281.25%29=+-4531.25+%2B+9062.5+-+2900\"
\n" ); document.write( "\"P%281.25%29+=+1631.25\"
\n" ); document.write( "The maximum profit is $1,631.25
\n" ); document.write( "I'll plot to check this:
\n" ); document.write( "\"+graph%28+600%2C+600%2C+-5%2C+3%2C+-200%2C+1800%2C+-2900x%5E2+%2B+7250x+-+2900%29+\"
\n" ); document.write( "Looks like I could be right
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