document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=26957>Question 26957</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 7x-3=6x I am not sure I understand the process explained by our instructor to find answers to problems like this where can I look on this site for help? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #14674 by </B><A HREF=/tutors/aboutme.mpl?userid=elima><B>elima(1433)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=elima><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=14674\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> On the home page of this site has a lot of different types of problems already solved. You can click on one of those links or just ask us.<BR>\n" );
document.write( "7x-3=6x<BR>\n" );
document.write( "first of all you want to get 3 to the other side, to do that you need to add 3 to both sides;<BR>\n" );
document.write( "7x-3+3=6x+3<BR>\n" );
document.write( "7x=6x+3<BR>\n" );
document.write( "Now you want 6x on the other side, so you subtract 6x from both sides;<BR>\n" );
document.write( "7x-6x=6x+3-6x<BR>\n" );
document.write( "add like terms;<BR>\n" );
document.write( "x=3<BR>\n" );
document.write( "Hope you understan, if not let me now!<BR>\n" );
document.write( "=) </SPAN>\n" );
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