document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=195663>Question 195663</A>: <I><SPAN STYLE=\"word-break: break-all;\"> two cards are drawn from a deck of 7 cards numbered 1 through 7. once a card is drawn, it is not replaced. find the probability of drawing a 4 and then a 6. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #146735 by </B><A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><B>jim_thompson5910(35256)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=146735\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> P(drawing a 4) = 1/7\r<BR>\n" );
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document.write( "once a 4 is drawn (and not put back), there are 6 cards left. So \r<BR>\n" );
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document.write( "P(drawing a 6 next) = 1/6\r<BR>\n" );
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document.write( "So ...\r<BR>\n" );
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document.write( "P(drawing a 4 then a 6) = P(drawing a 4) * P(drawing a 6 next) = (1/7)*(1/6) = (1*1)/(7*6) = 1/42 </SPAN>\n" );
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