document.write( "Question 195651This question is from textbook Algebra and Trigonometry Structure and Method book 2
\n" ); document.write( ": I have been working on this math problem and I can't seem to figure it out. I was wondering if someone could help me? Please and Thank You!!! I would deeply appreciate it!!\r
\n" ); document.write( "\n" ); document.write( "Find an equation of the parabola having vertex (0,0) and directrix y=2.
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Algebra.Com's Answer #146724 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
Keep in mind that the parabola form we'll use is \r
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\n" ); document.write( "\n" ); document.write( "\"%28x-h%29%5E2=4p%28y-k%29\" where \"p\" is the distance from the vertex to the focus.\r
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\n" ); document.write( "\n" ); document.write( "It turns out that the distance from the directrix to the vertex is equal to the distance from the vertex to the focus. Since the distance from the directrix y = 2 to the vertex (0,0) is 2 units, this means that \"p=2\"\r
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\n" ); document.write( "\n" ); document.write( "Also, since the vertex is (0,0), this means that \"h=0\" and \"k=0\"\r
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\n" ); document.write( "\n" ); document.write( "So all we need to do is plug these values in and isolate \"y\":\r
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\n" ); document.write( "\n" ); document.write( "\"%28x-h%29%5E2=4p%28y-k%29\" Start with the given equation.\r
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\n" ); document.write( "\n" ); document.write( "\"%28x-0%29%5E2=4%282%29%28y-0%29\" Plug in \"p=2\", \"h=0\" and \"k=0\"\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2=4%282%29y\" Simplify\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2=8y\" Multiply\r
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\n" ); document.write( "\n" ); document.write( "\"%281%2F8%29x%5E2=y\" Multiply both sides by \"1%2F8\" to isolate \"y\".\r
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\n" ); document.write( "\n" ); document.write( "\"y=%281%2F8%29x%5E2\" Rearrange the terms.\r
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\n" ); document.write( "\n" ); document.write( "Now because the parabola has the directrix above the vertex, this means that the parabola is opening down. So this means we need to attach a negative sign to the coefficient: \"y=-%281%2F8%29x%5E2\"\r
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\n" ); document.write( "\n" ); document.write( "So the equation is \"y=-%281%2F8%29x%5E2\"\r
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