document.write( "Question 195626: Hey there, Could someone please help me with the following homework question? It would be a great help.\r
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document.write( "Solve the following equation for 0 lesser than and equal to x lesser than and equal to 2 pi.\r
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document.write( "sinx = cos2x (5 marks) \n" );
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Algebra.Com's Answer #146705 by Alan3354(69443) You can put this solution on YOUR website! sinx = cos2x \n" ); document.write( "sin(x) = 1-2sin^2(x) \n" ); document.write( "2sin^2 + sin - 1 = 0 \n" ); document.write( "(2sin - 1)(sin + 1) = 0 \n" ); document.write( "sin = 1/2, sin = -1 \n" ); document.write( "---------------------- \n" ); document.write( "x = pi/6, 5pi/6 (from 1/2) \n" ); document.write( "x = 3pi/2 (sin = -1) \n" ); document.write( " \n" ); document.write( " |