document.write( "Question 195613: This is not from a text book but a question my instructor posed to me. I am not sure how to figure it out. Can someone please help me with it?\r
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document.write( "Suppose we have a list of zip codes that is only the 5-digit without the extension and there is no replacement or repetition. How many possible zip codes do we have?
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Algebra.Com's Answer #146702 by jim_thompson5910(35256)![]() ![]() ![]() You can put this solution on YOUR website! Note: I'm assuming that zero can be used as the first digit.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Method # 1:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Number of Possible Permutations = Number of Choices 1st Digit * Number of Choices 2nd Digit * Number of Choices 3rd Digit * Number of Choices 4th Digit * Number of Choices 5th Digit\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Number of Possible Permutations = 10 * 9 * 8 * 7 * 6\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Number of Possible Permutations = 30,240\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So there are 30,240 different zip codes\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "------------------------------------------------------------\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Method # 2\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Since there are 10 possible numbers to choose from and there are 5 positions to place them in, this means that \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Since order does matter, we must use the permutation formula:\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Expand 10! \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Expand 5! \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So 10 choose 5 (where order does matter) yields 30,240 unique permutations\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So once again, there are 30,240 different zip codes. \n" ); document.write( " \n" ); document.write( " |