document.write( "Question 195613: This is not from a text book but a question my instructor posed to me. I am not sure how to figure it out. Can someone please help me with it?\r
\n" ); document.write( "\n" ); document.write( "Suppose we have a list of zip codes that is only the 5-digit without the extension and there is no replacement or repetition. How many possible zip codes do we have?
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Algebra.Com's Answer #146702 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
Note: I'm assuming that zero can be used as the first digit.\r
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\n" ); document.write( "\n" ); document.write( "Method # 1:\r
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\n" ); document.write( "\n" ); document.write( "Number of Possible Permutations = Number of Choices 1st Digit * Number of Choices 2nd Digit * Number of Choices 3rd Digit * Number of Choices 4th Digit * Number of Choices 5th Digit\r
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\n" ); document.write( "\n" ); document.write( "Number of Possible Permutations = 10 * 9 * 8 * 7 * 6\r
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\n" ); document.write( "\n" ); document.write( "Number of Possible Permutations = 30,240\r
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\n" ); document.write( "\n" ); document.write( "So there are 30,240 different zip codes\r
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\n" ); document.write( "\n" ); document.write( "Method # 2\r
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\n" ); document.write( "\n" ); document.write( "Since there are 10 possible numbers to choose from and there are 5 positions to place them in, this means that \"n=10\" and \"r=5\"\r
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\n" ); document.write( "\n" ); document.write( "Since order does matter, we must use the permutation formula:\r
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\n" ); document.write( "\n" ); document.write( "\"n%21%2F%28n-r%29%21\" Start with the given formula\r
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\n" ); document.write( "\n" ); document.write( "\"10%21%2F%2810-5%29%21\" Plug in \"n=10\" and \"r=5\"\r
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\n" ); document.write( "\n" ); document.write( "\"10%21%2F5%21\" Subtract \"10-5\" to get 5\r
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\n" ); document.write( "\n" ); document.write( "Expand 10!
\n" ); document.write( "\"%2810%2A9%2A8%2A7%2A6%2A5%2A4%2A3%2A2%2A1%29%2F5%21\"\r
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\n" ); document.write( "\n" ); document.write( "Expand 5!
\n" ); document.write( "\"%2810%2A9%2A8%2A7%2A6%2A5%2A4%2A3%2A2%2A1%29%2F%285%2A4%2A3%2A2%2A1%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"%2810%2A9%2A8%2A7%2A6%2Across%285%2A4%2A3%2A2%2A1%29%29%2F%28cross%285%2A4%2A3%2A2%2A1%29%29\" Cancel\r
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\n" ); document.write( "\n" ); document.write( "\"10%2A9%2A8%2A7%2A6\" Simplify\r
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\n" ); document.write( "\n" ); document.write( "\"30240\" Now multiply 10*9*8*7*6 to get 30,240\r
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\n" ); document.write( "\n" ); document.write( "So 10 choose 5 (where order does matter) yields 30,240 unique permutations\r
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\n" ); document.write( "\n" ); document.write( "So once again, there are 30,240 different zip codes.
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