document.write( "Question 195548: 8c^2+21c+10=0 \n" ); document.write( "
Algebra.Com's Answer #146661 by jim_thompson5910(35256)\"\" \"About 
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\"8c%5E2%2B21c%2B10=0\" Start with the given equation.\r
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\n" ); document.write( "\n" ); document.write( "Notice we have a quadratic equation in the form of \"ac%5E2%2Bbc%2Bc\" where \"a=8\", \"b=21\", and \"c=10\"\r
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\n" ); document.write( "\n" ); document.write( "Let's use the quadratic formula to solve for c\r
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\n" ); document.write( "\n" ); document.write( "\"c+=+%28-b+%2B-+sqrt%28+b%5E2-4ac+%29%29%2F%282a%29\" Start with the quadratic formula\r
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\n" ); document.write( "\n" ); document.write( "\"c+=+%28-%2821%29+%2B-+sqrt%28+%2821%29%5E2-4%288%29%2810%29+%29%29%2F%282%288%29%29\" Plug in \"a=8\", \"b=21\", and \"c=10\"\r
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\n" ); document.write( "\n" ); document.write( "\"c+=+%28-21+%2B-+sqrt%28+441-4%288%29%2810%29+%29%29%2F%282%288%29%29\" Square \"21\" to get \"441\". \r
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\n" ); document.write( "\n" ); document.write( "\"c+=+%28-21+%2B-+sqrt%28+441-320+%29%29%2F%282%288%29%29\" Multiply \"4%288%29%2810%29\" to get \"320\"\r
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\n" ); document.write( "\n" ); document.write( "\"c+=+%28-21+%2B-+sqrt%28+121+%29%29%2F%282%288%29%29\" Subtract \"320\" from \"441\" to get \"121\"\r
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\n" ); document.write( "\n" ); document.write( "\"c+=+%28-21+%2B-+sqrt%28+121+%29%29%2F%2816%29\" Multiply \"2\" and \"8\" to get \"16\". \r
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\n" ); document.write( "\n" ); document.write( "\"c+=+%28-21+%2B-+11%29%2F%2816%29\" Take the square root of \"121\" to get \"11\". \r
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\n" ); document.write( "\n" ); document.write( "\"c+=+%28-21+%2B+11%29%2F%2816%29\" or \"c+=+%28-21+-+11%29%2F%2816%29\" Break up the expression. \r
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\n" ); document.write( "\n" ); document.write( "\"c+=+%28-10%29%2F%2816%29\" or \"c+=++%28-32%29%2F%2816%29\" Combine like terms. \r
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\n" ); document.write( "\n" ); document.write( "\"c+=+-5%2F8\" or \"c+=+-2\" Simplify. \r
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\n" ); document.write( "\n" ); document.write( "So the answers are \"c+=+-5%2F8\" or \"c+=+-2\"
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