document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=195544>Question 195544</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hi, I am having trouble figuring out this problem. What is the formula for figuring the height of a package when you have the base of the box?<BR>\n" );
document.write( "I know there must be some formula to use to figure it out. Thank you. \r<BR>\n" );
document.write( "\n" );
document.write( "Dimensions of a box. Rosita’s Christmas present from<BR>\n" );
document.write( "Carlos is in a box that has a width that is 3 inches shorter<BR>\n" );
document.write( "than the height. The length of the base is 5 inches longer<BR>\n" );
document.write( "than the height. If the area of the base is 84 square<BR>\n" );
document.write( "inches, then what is the height of the package? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #146660 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=146660\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> a box that has a width that is 3 inches shorter than the height.<BR>\n" );
document.write( " The length of the base is 5 inches longer than the height.<BR>\n" );
document.write( " If the area of the base is 84 square inches, <BR>\n" );
document.write( "then what is the height of the package?<BR>\n" );
document.write( ":<BR>\n" );
document.write( "Let x = the height<BR>\n" );
document.write( "then<BR>\n" );
document.write( "(x-3) = the width (which is 3\" shorter than the ht)<BR>\n" );
document.write( "and<BR>\n" );
document.write( "(x+5) = the length (which is 5\" longer than the ht)<BR>\n" );
document.write( ":<BR>\n" );
document.write( "The area of the base:<BR>\n" );
document.write( "(x-3)*(x+5) = 84<BR>\n" );
document.write( "x^2 + 2x - 15 = 84<BR>\n" );
document.write( "x^2 + 2x - 15 - 84 = 0<BR>\n" );
document.write( "x^2 + 2x - 99 = 0<BR>\n" );
document.write( "Factor<BR>\n" );
document.write( "(x+11)(x-9) = 0<BR>\n" );
document.write( "Positive solution is what we want here<BR>\n" );
document.write( "x = 9 inches is the height<BR>\n" );
document.write( ":<BR>\n" );
document.write( ";<BR>\n" );
document.write( "Check solution by finding the area of the base<BR>\n" );
document.write( "(9-3) * (9+5) =<BR>\n" );
document.write( "6 * 14 = 84 </SPAN>\n" );
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