document.write( "Question 26953: Can someone help?\r
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document.write( "The length of the longest leg of a triangle is twice the length of the shortest leg. The remaining leg is 2 inches longer than the shortest leg. If the perimeter of the triangle is 26 inches, how long is each leg? \n" );
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Algebra.Com's Answer #14666 by Earlsdon(6294)![]() ![]() ![]() You can put this solution on YOUR website! Let's call the longest leg A and the shortest leg C, so the middle leg will be B.\r \n" ); document.write( "\n" ); document.write( "Now, from the problem, we have: \n" ); document.write( "A = 2C and: \n" ); document.write( "B = C+2 and: \n" ); document.write( "A + B + C = 26 inches. So, if we substitute 2C for A and C+2 for B, we can solve for C.\r \n" ); document.write( "\n" ); document.write( "2C + C+2 + C = 26 Simplify. \n" ); document.write( "4C + 2 = 26 Subtract 2 from both sides of the equation. \n" ); document.write( "4C = 24 Divide both sides by 4. \n" ); document.write( "C = 6 Now that we have C, we can find A and B. \n" ); document.write( "A = 2C = 2(6) = 12 \n" ); document.write( "B = C+2 = 6+2 = 8\r \n" ); document.write( "\n" ); document.write( "Answer: \n" ); document.write( "The longest leg is 12 inches. \n" ); document.write( "The shortest leg is 6 inches. \n" ); document.write( "The remaining leg is 8 inches. \n" ); document.write( " |