document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=26931>Question 26931</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I have managed to work the rest of this question but the last bits are hell.Please help.   \r<BR>\n" );
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document.write( "I am trying to find the GRADIENT of the line PERPENDICULAR to AB\r<BR>\n" );
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document.write( "(i)<BR>\n" );
document.write( "A(3,2)................B(4,-1)\r<BR>\n" );
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document.write( "(ii)<BR>\n" );
document.write( "A(-6,3)...............B(6,3) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #14660 by </B><A HREF=/tutors/aboutme.mpl?userid=venugopalramana><B>venugopalramana(3286)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=venugopalramana><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.geocities.com/venugopalramana/FREE_MATHS_ASSISTANCE.html valign=middle><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=14660\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> gradient of line joining (x1,x2),(y1,y2)is given by (y2-y1)/(x2-x1)<BR>\n" );
document.write( "product gradients of 2 perpendicular lines =g1*g2 = -1<BR>\n" );
document.write( "so we have gradient of ab =(-1-2)/(4-3)=-3/1=-3=g1<BR>\n" );
document.write( "g2=-1/g1=-1/-3=1/3.............the other example also is similar\r<BR>\n" );
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document.write( "A(-6,3)...............B(6,3)<BR>\n" );
document.write( "g1=(3-3)/(6+6)=0=g1<BR>\n" );
document.write( "g2=-1/0= -infinity </SPAN>\n" );
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