document.write( "Question 195469: can you help me solve these problem?
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document.write( "An arrow is shot into the air with an upward velocity of 48 ft.per second from a hill 32 ft high.The height h of the arrow can be found using the model h=32 +48t -16t^ where t is the time in seconds.How many seconds after release will the arrow be 64 ft. above the ground?I will appreciate very much if you can help me. \n" );
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Algebra.Com's Answer #146594 by vleith(2983)![]() ![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "At what time is the height 64? \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "t = 1 and t =2\r \n" ); document.write( "\n" ); document.write( "It is at 64 feet in two places. First at 1 second in, then again at 2 seconds. \n" ); document.write( "Here is the graph of the arc. Note that the part of the graph to left of time=0, does not apply. \n" ); document.write( " |