document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=195410>Question 195410</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Respected sir,\r<BR>\n" );
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document.write( "1] A distance is covered in 3 hours 48 min. at 5 kmph. how much time will be taken to cover it at 28.5 kmph ?\r<BR>\n" );
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document.write( "2] Ritu goes to school at 10 kmph & reaches the school 6 minutes late.Nwxt day, she covers this distance at 12 kmper hour & reaches the school 9 minutes eariler than the scheduled time.what is the distance of her school from her house ?\r<BR>\n" );
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document.write( "plz sir help me to solve this arith problem.<BR>\n" );
document.write( "waiting for yurs reply.<BR>\n" );
document.write( "take care<BR>\n" );
document.write( "thank u. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #146586 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=146586\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 1] A distance is covered in 3 hours 48 min. at 5 kmph. how much time will be taken to cover it at 28.5 kmph ?<BR>\n" );
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document.write( "Convert 3 hr 48 min to hrs; 3 + 48/60 = 3.8 hrs<BR>\n" );
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document.write( "we can use inverted ratio here, (Time varies inversely to speed)<BR>\n" );
document.write( "let t = time to cover the dist at 28.5 km/hr<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=5%2F28.5 ALIGN=MIDDLE  ALT=\"5%2F28.5\"   DISABLED_style= \"max-width:90%; height:auto;\" > = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=t%2F3.8 ALIGN=MIDDLE  ALT=\"t%2F3.8\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "Cross multiply<BR>\n" );
document.write( "28.5t = 5*3.8<BR>\n" );
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document.write( "28.5t = 19<BR>\n" );
document.write( "t = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=19%2F28.5 ALIGN=MIDDLE  ALT=\"19%2F28.5\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "t = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2%2F3 ALIGN=MIDDLE  ALT=\"2%2F3\"   DISABLED_style= \"max-width:90%; height:auto;\" > hr to cover that dist at 28.5 km<BR>\n" );
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document.write( "Check solution by finding the dist at each speed and time<BR>\n" );
document.write( ".67 * 28.5 ~ 19 km<BR>\n" );
document.write( "3.8 * 5 = 19 km<BR>\n" );
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document.write( "2] Rita goes to school at 10 kmph & reaches the school 6 minutes late.<BR>\n" );
document.write( "Next day, she covers this distance at 12 km/hr & reaches the school 9<BR>\n" );
document.write( "minutes earlier than the scheduled time. <BR>\n" );
document.write( "What is the distance of her school from her house?<BR>\n" );
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document.write( "Let's just say the time difference between the two trips is 15 min, which <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=1%2F4 ALIGN=MIDDLE  ALT=\"1%2F4\"   DISABLED_style= \"max-width:90%; height:auto;\" >hr<BR>\n" );
document.write( "Write a time equation Time = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=dist%2Fspeed ALIGN=MIDDLE  ALT=\"dist%2Fspeed\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "12 km time + <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=1%2F4 ALIGN=MIDDLE  ALT=\"1%2F4\"   DISABLED_style= \"max-width:90%; height:auto;\" >hr = 10 km time <BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=d%2F12 ALIGN=MIDDLE  ALT=\"d%2F12\"   DISABLED_style= \"max-width:90%; height:auto;\" > + <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=1%2F4 ALIGN=MIDDLE  ALT=\"1%2F4\"   DISABLED_style= \"max-width:90%; height:auto;\" > = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=d%2F10 ALIGN=MIDDLE  ALT=\"d%2F10\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "Multiply equation by 60 to get rid of the denominators, results:<BR>\n" );
document.write( "5d + 15 = 6d<BR>\n" );
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document.write( "15 = 6d - 5d<BR>\n" );
document.write( "d = 15 km is the distance<BR>\n" );
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document.write( "Check solution by finding the time of each trip<BR>\n" );
document.write( "15/10 = 1.5 hr<BR>\n" );
document.write( "15/12 = 1.25 hr<BR>\n" );
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document.write( "differ= .25 hr which is 15 min\r<BR>\n" );
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