document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=195436>Question 195436</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The width of a rectangle is 6 kilometers less than twice it's length. If it's area is 176 square kilometers, find the dimensions of the rectangle. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #146575 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=146575\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> W=2L-6<BR>\n" );
document.write( "AREA=WL<BR>\n" );
document.write( "176=(2L-6)L<BR>\n" );
document.write( "176=2L^2-6L<BR>\n" );
document.write( "2L^2-6L-176=0<BR>\n" );
document.write( "2(L^2-3L-88)=0<BR>\n" );
document.write( "2(L-11)(L+8)=0<BR>\n" );
document.write( "L-11=0<BR>\n" );
document.write( "L=11 ANS. FOR THE LENGTH.<BR>\n" );
document.write( "W=2*11-6<BR>\n" );
document.write( "W=22-6<BR>\n" );
document.write( "W=16 ANS.<BR>\n" );
document.write( "PROOF:<BR>\n" );
document.write( "176=11*16<BR>\n" );
document.write( "176=176 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );