document.write( "Question 195438: two consecutive odd intergers have a product of 99. find the larger number. \n" ); document.write( "
Algebra.Com's Answer #146566 by nerdybill(7384)![]() ![]() You can put this solution on YOUR website! two consecutive odd intergers have a product of 99. find the larger number. \n" ); document.write( ". \n" ); document.write( "Let x = smaller consecutive odd integer \n" ); document.write( "then \n" ); document.write( "x+2 = larger consecutive odd integer \n" ); document.write( ". \n" ); document.write( "x(x+2) = 99 \n" ); document.write( "x^2 + 2x = 99 \n" ); document.write( "x^2 + 2x - 99 = 0 \n" ); document.write( "(x+11)(x-9) = 0 \n" ); document.write( "x = {-11,9} \n" ); document.write( ". \n" ); document.write( "the larger odd integers would then be: \n" ); document.write( "x = {-9,11} \n" ); document.write( ". \n" ); document.write( "Therefore, TWO possible sets: \n" ); document.write( "-11 and -9 \n" ); document.write( "OR \n" ); document.write( "9 and 11 \n" ); document.write( ". \n" ); document.write( "Therefore, the answer could either be -9 or 11 \n" ); document.write( "If they want the positive solution it would be 11 \n" ); document.write( " |