document.write( "Question 195438: two consecutive odd intergers have a product of 99. find the larger number. \n" ); document.write( "
Algebra.Com's Answer #146566 by nerdybill(7384)\"\" \"About 
You can put this solution on YOUR website!
two consecutive odd intergers have a product of 99. find the larger number.
\n" ); document.write( ".
\n" ); document.write( "Let x = smaller consecutive odd integer
\n" ); document.write( "then
\n" ); document.write( "x+2 = larger consecutive odd integer
\n" ); document.write( ".
\n" ); document.write( "x(x+2) = 99
\n" ); document.write( "x^2 + 2x = 99
\n" ); document.write( "x^2 + 2x - 99 = 0
\n" ); document.write( "(x+11)(x-9) = 0
\n" ); document.write( "x = {-11,9}
\n" ); document.write( ".
\n" ); document.write( "the larger odd integers would then be:
\n" ); document.write( "x = {-9,11}
\n" ); document.write( ".
\n" ); document.write( "Therefore, TWO possible sets:
\n" ); document.write( "-11 and -9
\n" ); document.write( "OR
\n" ); document.write( "9 and 11
\n" ); document.write( ".
\n" ); document.write( "Therefore, the answer could either be -9 or 11
\n" ); document.write( "If they want the positive solution it would be 11
\n" ); document.write( "
\n" );