document.write( "Question 195281: find the dimensions of the figure.
\n" ); document.write( "triangle; area is 12 cm squared, base is x and the height is x+2 cm
\n" ); document.write( "rectangle; area is 160ft squared, length is x ft.and the width is x-12 ft.
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Algebra.Com's Answer #146553 by honey143(2)\"\" \"About 
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\n" ); document.write( "1) Area of Triangle = (1/2)base x height\r
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\n" ); document.write( "\n" ); document.write( "Substituting given:
\n" ); document.write( "\"12cm%5E2=%281%2F2%29%28x%29%28x%2B2%29\"
\n" ); document.write( "Cross multiply/ expand:
\n" ); document.write( "\"12%2A2=x%2A2%2B2x\"
\n" ); document.write( "Combine all terms:
\n" ); document.write( "\"x%5E2%2B2x-24=0\"
\n" ); document.write( "\"%28x%2B6%29%28x-4%29=0\"
\n" ); document.write( "\"x=-6\", disregard
\n" ); document.write( "\"highlight%28red%28x=4cm%29%29\", base
\n" ); document.write( "Also, \"4%2B2=highlight%28red%286cm%29%29\", height\r
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\n" ); document.write( "\n" ); document.write( "Check,
\n" ); document.write( "\"12cm%5E2=%281%2F2%29%284%29%286%29\"
\n" ); document.write( "\"12cm%5E2=%281%2F2%2924cm%5E2\"
\n" ); document.write( "\"12cm%5E2=12cm%5E2\"\r
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\n" ); document.write( "\n" ); document.write( "2) Area of Rectangle = Length x Width\r
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\n" ); document.write( "\n" ); document.write( "Substitue given:
\n" ); document.write( "\"160ft%5E2=%28x%29%28x-12%29\"
\n" ); document.write( "\"160=x%5E2-12x\"
\n" ); document.write( "\"x%5E2-12x-160=0\"
\n" ); document.write( "\"%28x%2B8%29%28x-20%29=0\"
\n" ); document.write( "\"x=-8\", disregard \"-\"
\n" ); document.write( "\"highlight%28red%28x=20ft%29%29\", Length
\n" ); document.write( "Also, \"20-12=highlight%28red%288ft%29%29\", Width\r
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\n" ); document.write( "\n" ); document.write( "Check,
\n" ); document.write( "\"160ft%5E2=20%2A8\"
\n" ); document.write( "\"160ft%5E2=160ft%5E2\"\r
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