document.write( "Question 195186: Kathrin and Tom together clean the garage in 3 hours. Seperatly, it takes Tom one hour more then Kathrin. How long does it take the to clean the garage seperatly? Approximate to the nearest tenth of an hour. \n" ); document.write( "
Algebra.Com's Answer #146532 by ankor@dixie-net.com(22740) You can put this solution on YOUR website! Kathrin and Tom together clean the garage in 3 hours. \n" ); document.write( "Separatly, it takes Tom one hour more then Kathrin. \n" ); document.write( " How long does it take the to clean the garage seperatly? \n" ); document.write( " Approximate to the nearest tenth of an hour. \n" ); document.write( "; \n" ); document.write( "Let t = time required for K to do the job alone \n" ); document.write( "then \n" ); document.write( "(t+1) = time for T to do the same job alone \n" ); document.write( ": \n" ); document.write( "let the completed job = 1 \n" ); document.write( ": \n" ); document.write( "Each will do a fraction of the job; the two fractions add up to 1 \n" ); document.write( ": \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( "Multiply equation by t(t+1) \n" ); document.write( "t(t+1)* \n" ); document.write( "cancel out the denominators and you have: \n" ); document.write( "3(t+1) + 3t = t(t+1) \n" ); document.write( ": \n" ); document.write( "3t + 3 + 3t = t^2 + t \n" ); document.write( ": \n" ); document.write( "6t + 3 = t^2 + t \n" ); document.write( "arrange as a quadratic equation \n" ); document.write( "0 = t^2 + t - 6t - 3 \n" ); document.write( ": \n" ); document.write( "t^2 - 5t -3 = 0 \n" ); document.write( "Use the quadratic formula; a=1; b=-5; c=-3 \n" ); document.write( ": \n" ); document.write( "Do math here: \n" ); document.write( " \n" ); document.write( "the positive solution: \n" ); document.write( "t = 5.54 hrs, is K's time alone \n" ); document.write( "and \n" ); document.write( "6.54 = T's time alone\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |