document.write( "Question 195311This question is from textbook Introductory Algebra
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document.write( ": If Bill drives from his home to his office at 40 miles per hour, he arrives 5 minutes early. If he drives at 30 miles per hour, he arrives 5 minutes late. How far is it from his home to his office? \n" );
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Algebra.Com's Answer #146501 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! If Bill drives from his home to his office at 40 miles per hour, he arrives 5 \n" ); document.write( "minutes early. \n" ); document.write( "If he drives at 30 miles per hour, he arrives 5 minutes late. How far is it from his home to his office? \n" ); document.write( ": \n" ); document.write( "Just assume, the difference in the two trips is 10 min; \n" ); document.write( ": \n" ); document.write( "Let t = time at 40 mph \n" ); document.write( "then \n" ); document.write( "(t + \n" ); document.write( "Write distance equation; dist = speed * time \n" ); document.write( "40t = 30(t+ \n" ); document.write( "40t = 30t + 5 \n" ); document.write( ": \n" ); document.write( "40t - 30t = 5 \n" ); document.write( ": \n" ); document.write( "10t = 5 \n" ); document.write( "t = \n" ); document.write( "t = \n" ); document.write( ": \n" ); document.write( "Find the distance \n" ); document.write( "40 * \n" ); document.write( "Check the solution by finding the distance at 30 mph \n" ); document.write( "30 * \n" ); document.write( "30 * \n" ); document.write( " \n" ); document.write( " |