document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=195302>Question 195302</A>: <I><SPAN STYLE=\"word-break: break-all;\">  HOW MANY LITERS OF A 30% ALCHOHOL SOLUTION MUST BE MIXED WITH 40LITERS OF 90% SOLUTION TO GET A 50%SOLUTION? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #146485 by </B><A HREF=/tutors/aboutme.mpl?userid=ptaylor><B>ptaylor(2198)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ptaylor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ptaylor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=146485\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x=amount of 30% solution needed\r<BR>\n" );
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document.write( "Now we know that the amount of pure alcohol in the 30% mixture (0.30x) plus the amount of pure alcohol in the 40 liters (0.90*40) has to equal the amount of pure alcohol in the final mixture (0.50(40+x), so:\r<BR>\n" );
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document.write( "0.30x+0.90*40=0.50(40+x)  get rid of parens<BR>\n" );
document.write( "0.30x+36=20+0.50x  subtract 36 and also 0.50x from each side<BR>\n" );
document.write( "0.30x-0.50x+36-36=20-36<BR>\n" );
document.write( "-0.20x=-16  divide each side by -0.20<BR>\n" );
document.write( "x=80 liters-------------------amount of 30% solution needed\r<BR>\n" );
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document.write( "CK<BR>\n" );
document.write( "0.30*80+0.90*40=0.50(120)<BR>\n" );
document.write( "24+36=60<BR>\n" );
document.write( "60=60\r<BR>\n" );
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document.write( "Hope this helps---ptaylor<BR>\n" );
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