document.write( "Question 195268This question is from textbook
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document.write( ": STANBON You helped me with this problem:
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document.write( "The level of thorium in a sample decreases by a factor of one-half every 2 million years. A meteorite is discovered to have only 8.6% of its original thorium remaining. How old is the meteorite? I already have the answer, but need to know
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document.write( " What does Ao represent? Do you know what the value of Ao? What does t represent? What are the units of t? Thanks!
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document.write( "A(t) = Ao*(1/2)^(t/2*10^6)
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document.write( "0.086Ao = Ao*(1/2)^(t/(2 million))
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document.write( "(1/2)^(t/2 million) = 0.086
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document.write( "Take the log to get:
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document.write( "(t/2 million) = log(0.086)/log(1/2) = 3.53951953
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document.write( "t = (2 million)*(3.53951953)
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document.write( "t = 7,079,039.06 \n" );
document.write( "
Algebra.Com's Answer #146460 by stanbon(75887) ![]() You can put this solution on YOUR website! You helped me with this problem: \n" ); document.write( "The level of thorium in a sample decreases by a factor of one-half every 2 million years. A meteorite is discovered to have only 8.6% of its original thorium remaining. How old is the meteorite? I already have the answer, but need to know \n" ); document.write( "What does Ao represent? Do you know what the value of Ao? What does t represent? What are the units of t? Thanks!\r \n" ); document.write( "\n" ); document.write( "----------- \n" ); document.write( "A(t) = Ao*(1/2)^(t/2*10^6) \n" ); document.write( "A(t) is the amount of material you have at time \"t\". \n" ); document.write( "Ao is the amount of material you have in the beginning: at time t=0 \n" ); document.write( "In your problem you do not know the amount at time t=0, so you \n" ); document.write( "do not know Ao. But since you have it on both sides of the equation, \n" ); document.write( "it cancels out. \n" ); document.write( "In your problem t represets the number of years the thorium has \n" ); document.write( "been around (presumably in the meteorite). \n" ); document.write( "----------------------- \n" ); document.write( "0.086Ao = Ao*(1/2)^(t/(2 million)) \n" ); document.write( "(1/2)^(t/2 million) = 0.086 \n" ); document.write( "Take the log to get: \n" ); document.write( "(t/2 million) = log(0.086)/log(1/2) = 3.53951953 \n" ); document.write( "t = (2 million)*(3.53951953) \n" ); document.write( "t = 7,079,039.06 years \n" ); document.write( "============================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " \n" ); document.write( " |