document.write( "Question 195256: Jess invested $30 more at 6% than at 5%. If the total annual interest is $100, how much is invested at each rate?\r
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Algebra.Com's Answer #146454 by stanbon(75887)\"\" \"About 
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Jess invested $30 more at 6% than at 5%. If the total annual interest is $100, how much is invested at each rate?
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\n" ); document.write( "Equations:
\n" ); document.write( "Quantity Eq. : x = y + 30
\n" ); document.write( "Interest Eq. :0.06x + 0.05y = 100
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\n" ); document.write( "Substitute:
\n" ); document.write( "0.06(y+30) + 0.05y = 100
\n" ); document.write( "Multiply thru by 100 to get:
\n" ); document.write( "6(y+30) + 5y = 10000
\n" ); document.write( "6y + 180 + 5y = 10000
\n" ); document.write( "11y = 9820
\n" ); document.write( "y = $892.73 (amount invested at 5%)
\n" ); document.write( "x = y + 30 = 892.73 + 30 = $922.73 (amount invested at 6%)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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