document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=195244>Question 195244</A>: <I>LIST SEPARATELY, if possible, two NEGATIVE INTEGERS such that one is double the other and their product is 98. \r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #146448 by </B><A HREF=/tutors/aboutme.mpl?userid=windsolace><B>windsolace(8)</B></A><IMG SRC=http://www.algebra.com/images/stars/stars-05.gif>&nbsp;<A HREF=/tutors/aboutme.mpl?userid=windsolace><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=146448\">put this solution on YOUR website!</A><BR>Let the smaller unknown number be x. <BR>\n" );
document.write( "Therefore the larger number is 2x\r<BR>\n" );
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document.write( "x * 2x = 2(x^2)<BR>\n" );
document.write( "2(x^2) = 98<BR>\n" );
document.write( "x^2 = 98/2<BR>\n" );
document.write( "x^2 = 49<BR>\n" );
document.write( "x = 7\r<BR>\n" );
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document.write( "Since both integers are negative, therefore the 2 integers are -7 and -14<BR>\n" );
document.write( "To test:<BR>\n" );
document.write( "(-7) * (-14) = 98\r<BR>\n" );
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document.write( "I used * as multiply because x is already used as a constant in the solution. Don't want you people to get mixed up. =)</TD></TR></TABLE>\n" );