document.write( "Question 195220: what is log (x - 48) + logx =2? \n" ); document.write( "

Algebra.Com's Answer #146416 by nerdybill(7384) $\"\"$ $\"About$

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Applying \"log rules\":\r
\n" ); document.write( "\n" ); document.write( "log (x - 48) + logx =2?
\n" ); document.write( "log (x-48)x = 2
\n" ); document.write( "(x-48)x = 10^2
\n" ); document.write( "x^2 - 48x = 100
\n" ); document.write( "x^2 - 48x - 100 = 0
\n" ); document.write( "(x-50)(x+2) = 0
\n" ); document.write( "x = {-2, 50}
\n" ); document.write( "Since log of negative numbers doesn't make sense, throw it out leaving:
\n" ); document.write( "x = 50
\n" ); document.write( " \n" ); document.write( "

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