document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=195226>Question 195226</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Finding all real or imaginary solutions. I am not getting this.<BR>\n" );
document.write( "3v^2 + 4v -1 = 0<BR>\n" );
document.write( " So far I did this<BR>\n" );
document.write( "3v^2 - 4v = 1<BR>\n" );
document.write( "3v^2 -4v +4 = 1+4 after this I am confused. Please help. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #146413 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=146413\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Finding all real or imaginary solutions. I am not getting this.<BR>\n" );
document.write( "3v^2 + 4v -1 = 0<BR>\n" );
document.write( "v = [-4 +- sqrt(16 - 4*3*-1)]/6<BR>\n" );
document.write( "v = [-4 +- sqrt(28)]/6<BR>\n" );
document.write( "v = [-4 +- 2sqrt(7)]/6<BR>\n" );
document.write( "v = (-2/3) + (1/3)sqrt(7) or (-2/3) - (1/3)sqrt(7)<BR>\n" );
document.write( "=======================================================<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );