document.write( "Question 195121: simplify the expression,\r
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\n" ); document.write( "\n" ); document.write( "so the question says... one half minus to the cube root of three over 2 multiplied by \"i\". all to the third power.
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Algebra.Com's Answer #146361 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
Are you sure that it's not a square root and the expression is \"%281%2F2-%28sqrt%283%29%2F2%29%2Ai%29%5E3\"??? If so, then...\r
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\n" ); document.write( "\n" ); document.write( "Take note that \"cos%2860%29=1%2F2\" and \"sin%2860%29=sqrt%283%29%2F2\". So this means that\r
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\n" ); document.write( "\n" ); document.write( "\"%281%2F2-%28sqrt%283%29%2F2%29%2Ai%29%5E3\" Start with the given expression.\r
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\n" ); document.write( "\n" ); document.write( "\"%28cos%2860%29-sin%2860%29%2Ai%29%5E3\" Replace \"1%2F2\" with \"cos%2860%29\". Replace \"sqrt%283%29%2F2\" with \"sin%2860%29\" (see above)\r
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\n" ); document.write( "\n" ); document.write( "\"cos%2860%2A3%29-sin%2860%2A3%29%2Ai\" Use De Moivre's formula to expand.\r
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\n" ); document.write( "\n" ); document.write( "\"cos%28180%29-sin%28180%29%2Ai\" Multiply\r
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\n" ); document.write( "\n" ); document.write( "\"-1-0%2Ai\" Evaluate the trig functions.\r
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\n" ); document.write( "\n" ); document.write( "\"-1\" Simplify\r
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\n" ); document.write( "\n" ); document.write( "So \"%281%2F2-%28sqrt%283%29%2F2%29%2Ai%29%5E3=-1\"
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