document.write( "Question 195111: Two pipes are connected to a tank. When working together, the two pipes can fill the tank in 4 hours. The larger pipe, working alone, can fill the tank in 6 less hours than the smaller one. How long would the smaller one take to fill the tank alone? \n" ); document.write( "
Algebra.Com's Answer #146357 by ankor@dixie-net.com(22740)\"\" \"About 
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Two pipes are connected to a tank. When working together, the two pipes can fill
\n" ); document.write( "the tank in 4 hours. The larger pipe, working alone, can fill the tank in 6 less
\n" ); document.write( " hours than the smaller one. How long would the smaller one take to fill the tank alone?
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\n" ); document.write( "Let t = time for the small pipe to fill the tank alone
\n" ); document.write( "Then
\n" ); document.write( "(t-6) = time for the large pipe to fill the tank alone
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\n" ); document.write( "Let the full tank = 1
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\n" ); document.write( "Each tank will fill a fraction of the tank. The two fractions = 1
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\n" ); document.write( "\"4%2Ft\" + \"4%2F%28%28t-6%29%29\" = 1
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\n" ); document.write( "Multiply by t(t-6)
\n" ); document.write( "t(t-6)*\"4%2Ft\" + t(t-6)*\"4%2F%28%28t-6%29%29\" = t(t-6)(1)
\n" ); document.write( "Cancel out the denominators and you have:
\n" ); document.write( "4(t-6) + 4t = t(t-6)
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\n" ); document.write( "4t - 24 + 4t = t^2 - 6t
\n" ); document.write( "Arrange as a quadratic equation
\n" ); document.write( "0 = t^2 - 6t - 8t + 24
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\n" ); document.write( "t^2 - 14t + 24 = 0
\n" ); document.write( "Factor this to
\n" ); document.write( "(t-2)(t-12) = 0
\n" ); document.write( "The only reasonable solution
\n" ); document.write( "t = 12 hrs, the small pipe alone
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\n" ); document.write( "Check solution in original equation, (large pipe alone:12-6 = 6hr)
\n" ); document.write( "\"4%2F12\" + \"4%2F6%29\" = 1
\n" ); document.write( "\"1%2F3\" + \"2%2F3%29\" = 1
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