document.write( "Question 26878: I don't understand how to come up with the answer to this equation:\r
\n" ); document.write( "\n" ); document.write( " $\"5%2F%28x%2B3%29=10%2F%282-x%29\"$ . The answer is -20/15=-4/3. Can you explain this to me.\r
\n" ); document.write( "\n" ); document.write( "Thanks \n" ); document.write( "

Algebra.Com's Answer #14633 by bmauger(101) $\"\"$ $\"About$

You can put this solution on YOUR website!
To solve this type of problem you must cross multiply. That means that you take the denominator from one side of the equation and multiply it by the numerator of the other equation, and set it equal to the product of the remaining denominator and numerator:\r
\n" ); document.write( "\n" ); document.write( " $\"5%2F%28x%2B3%29=10%2F%282-x%29\"$
\n" ); document.write( "Cross multiply:
\n" ); document.write( " $\"5%282-x%29=10%28x%2B3%29\"$
\n" ); document.write( "Distribute:
\n" ); document.write( " $\"10-5x=10x%2B30\"$
\n" ); document.write( "Rearrange:
\n" ); document.write( " $\"-15x=20\"$
\n" ); document.write( "Solve:
\n" ); document.write( " $\"x=20%2F%28-15%29=-4%2F3\"$ \n" ); document.write( "

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