document.write( "Question 26872: HELP!
\n" ); document.write( "Latoya is twice as old as her cousin was 3 years ago. If the sum of their ages now is 15, how old is each one of them?
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Algebra.Com's Answer #14631 by bmauger(101)\"\" \"About 
You can put this solution on YOUR website!
This is a matter of converting English into algebra, so let's look at it word by word.\r
\n" ); document.write( "\n" ); document.write( "\"Latoya\" - let's create the variable L to stand for Latoya's age
\n" ); document.write( "\"is\" - means \"=\"
\n" ); document.write( "\"twice as old as\" means we will be multiplying by 2.
\n" ); document.write( "\"her cousin\" - we need a new variable C to represent her cousin's age
\n" ); document.write( "\"was three years ago\" - 3 years ago means we will have to subtract 3\r
\n" ); document.write( "\n" ); document.write( "So our first sentence boils down to \"Latoya (L) is (=) twice as old as (2 times) her cousin (C) three years ago (-3)\" or:
\n" ); document.write( "\"L=2C-3\"
\n" ); document.write( "The second part says:
\n" ); document.write( "\"The sum of\" - means we'll be adding together
\n" ); document.write( "\"their ages now\" - L & C
\n" ); document.write( "\"is\" - still means equals
\n" ); document.write( "\"15\" - 15
\n" ); document.write( "This translates to:
\n" ); document.write( "\"L%2BC=15\"
\n" ); document.write( "Now you have two equations, that you can solve either through elimination, substitution, graphing, or any other way you've been taught to solve for the ages of each L & C.
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