document.write( "Question 194984: please help me out........... \r
\n" );
document.write( "
\n" );
document.write( "\n" );
document.write( "-54=10-(m-10)^3/2 \n" );
document.write( "
Algebra.Com's Answer #146289 by stanbon(75887) ![]() You can put this solution on YOUR website! -54=10-(m-10)^3/2 \n" ); document.write( "--- \n" ); document.write( "(m - 10)^(3/2) = 64 \n" ); document.write( "--- \n" ); document.write( "Raise both sides to the 2/3 power to get: \n" ); document.write( "m - 10 = 64^(2/3) \n" ); document.write( "-------- \n" ); document.write( "Take the cube root of the right side: \n" ); document.write( "m-10 = 4^2 \n" ); document.write( "Square the right side \n" ); document.write( "m - 10 = 16 \n" ); document.write( "m = 26 \n" ); document.write( "============ \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |