document.write( "Question 195004: A man made a 70-mile trip at a certain average rate. By increasing his average rate by 5 miles per hour, he traveled 80 miles in the same time that he spent on the 70-mile trip. Find his average rate on each trip. \n" ); document.write( "
Algebra.Com's Answer #146286 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! A man made a 70-mile trip at a certain average rate. \n" ); document.write( " By increasing his average rate by 5 miles per hour, he traveled 80 miles in \n" ); document.write( "the same time that he spent on the 70-mile trip. Find his average rate on each trip. \n" ); document.write( ": \n" ); document.write( "Let s = the original speed (70 mi trip) \n" ); document.write( "then \n" ); document.write( "(s+5) = the speed required for the 80 mi trip \n" ); document.write( ": \n" ); document.write( "The two trips have equal time; write a time equation; Time = \n" ); document.write( ": \n" ); document.write( "80 mi time = 70 mi time \n" ); document.write( " \n" ); document.write( "Cross multiply and you have: \n" ); document.write( "80s = 70(s+5) \n" ); document.write( ": \n" ); document.write( "80s = 70s + 350 \n" ); document.write( ": \n" ); document.write( "80s - 70s = 350 \n" ); document.write( ": \n" ); document.write( "10s = 350 \n" ); document.write( "s = \n" ); document.write( "s = 35 mph original speed \n" ); document.write( "then \n" ); document.write( "35 + 5 = 40 mph is the faster speed \n" ); document.write( "; \n" ); document.write( ": \n" ); document.write( "Check solution by finding the time of each trip \n" ); document.write( "70/35 = 2 hr \n" ); document.write( "80/40 = 2 hr \n" ); document.write( " |