document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=194977>Question 194977</A>: <I><SPAN STYLE=\"word-break: break-all;\"> hi. im having a really hard time solving a logarithmic equation. heres the first problem log4 x=3/2 can you explain it to me? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #146262 by </B><A HREF=/tutors/aboutme.mpl?userid=nerdybill><B>nerdybill(7384)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nerdybill><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nerdybill><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=146262\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Apply \"log rules\"<BR>\n" );
document.write( "You can review them at:<BR>\n" );
document.write( "http://www.purplemath.com/modules/logrules.htm<BR>\n" );
document.write( ".<BR>\n" );
document.write( "log4 x=3/2 <BR>\n" );
document.write( "x = 4^(3/2)<BR>\n" );
document.write( "x = sqrt(4^3)<BR>\n" );
document.write( "x = sqrt(64)<BR>\n" );
document.write( "x = +- 8<BR>\n" );
document.write( ".<BR>\n" );
document.write( "We can toss out the negative solution because you can't take a log of a negative number.<BR>\n" );
document.write( "Therefore,<BR>\n" );
document.write( "x = 8<BR>\n" );
document.write( " </SPAN>\n" );
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