document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=194734>Question 194734</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A boat can go 40 miles against the current in the same time it can go 80 miles with the current. If the speed of the current is 2 miles per hour, what is the speed of the boat? \r<BR>\n" );
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document.write( "This problem does not give time, it just states that it is the same, thus making me confused on how to solve it. Please help.... </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #146152 by </B><A HREF=/tutors/aboutme.mpl?userid=solver91311><B>solver91311(24713)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=solver91311><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=solver91311><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=146152\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <font face=\"Garamond\" size=\"+2\">\r<BR>\n" );
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document.write( "If the boat goes twice as far, it must be going twice as fast.  So if the speed of the boat in still water is <b><i>r</i></b>, then it must be going <b><i>r</i> - 2</b> against the 2 mph current, and <b><i>r</i> + 2</b> with the current.\r<BR>\n" );
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document.write( "And since it is going twice as fast with the current as against the current:\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE \ \ \ \ \ \ \ \ \ \ r + 2 = 2(r - 2)\">\r<BR>\n" );
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document.write( "Just solve for <b><i>r</i></b>.\r<BR>\n" );
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document.write( "John<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE e^{i\pi} + 1 = 0\"><BR>\n" );
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