document.write( "Question 194802: I have these 3 problems left and i cannot figure them out someone please help asap id really appreciate it.\r
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document.write( "Solve the equation for x.\r
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document.write( "1.\r
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document.write( "2.\r
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document.write( "3. \n" );
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Algebra.Com's Answer #146137 by RAY100(1637)![]() ![]() ![]() You can put this solution on YOUR website! 1) sqrt (x) -5 =7 \n" ); document.write( ",,,,sqrt(x) =12 \n" ); document.write( "squaring \n" ); document.write( "x = 144 \n" ); document.write( "checking \n" ); document.write( "sqrt(144) -5 =12-5 =7,,,,ok \n" ); document.write( "or if the problem is \n" ); document.write( "sqrt (x-5) =7 \n" ); document.write( "squaring \n" ); document.write( "x-5 =49 \n" ); document.write( "x=54 \n" ); document.write( "checking \n" ); document.write( "sqrt(54-5) = sqrt(49) =7,,,ok \n" ); document.write( ". \n" ); document.write( "2) sqrt (3x) / sqrt(2x+3) =2 \n" ); document.write( "squaring \n" ); document.write( "(3x) / (2x+3) = 4 \n" ); document.write( "cross multiply \n" ); document.write( "3x = 4 (2x+3) = 8x +12 \n" ); document.write( "-5x = 12 \n" ); document.write( "x=(-12/5) ,,,,,,ANSWER \n" ); document.write( "checking \n" ); document.write( "sqrt(3(-12/5) / sqrt( 2(-12/5) +3) = 2 \n" ); document.write( "sqrt -36/5 / sqrt (-24 /5 +3) =2 \n" ); document.write( "sqrt -36/5 / sqrt ( -24/5 +15/5) =2 \n" ); document.write( "sqrt -36 /5 / sqrt -9/5 =2 \n" ); document.write( "sqrt ( -36 /-9) = sqrt (4) =2 \n" ); document.write( "2=2,,,,,,ok \n" ); document.write( ". \n" ); document.write( "3) sqrt(x+5) = x+3 \n" ); document.write( "squaring \n" ); document.write( "(x+5) = (x+3)^2 = (x+3)(x+3) =x^2 +6x +9 \n" ); document.write( "0 = x^2 +5x +4 \n" ); document.write( "0 = ( x+1) (x+4) \n" ); document.write( "x = -1, -4 \n" ); document.write( "checking \n" ); document.write( "x=-1 ,,,, sqrt(-1+5) = (-1+3),,,,sqrt 4 = 2,,,,,,,ok \n" ); document.write( "for x=-4,,,,,,sqrt ( -4+5) = (-4+3),,,sqrt (1) = -1,,, ok,,,realizing sqrt1= +/- 1 \n" ); document.write( " |