document.write( "Question 194785: i have to write an equation of the line that is tangent to the circle at that point:\r
\n" ); document.write( "\n" ); document.write( "x^2+y^2=50; (-7,1)
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Algebra.Com's Answer #146117 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
First, answer the question: \"Is the point (-7,1)
\n" ); document.write( "on the circle?\"
\n" ); document.write( "\"x%5E2+%2B+y%5E2+=+50\"
\n" ); document.write( "\"%28-7%29%5E2+%2B+1%5E2+=+50\"
\n" ); document.write( "\"49+%2B+1+=+50\"
\n" ); document.write( "\"50+=+50\" Yes
\n" ); document.write( "The center of the circle is the origin.
\n" ); document.write( "Next find the equation of the line that
\n" ); document.write( "contains the points (0,0) and (-7,1)
\n" ); document.write( "\"%28y+-+1%29+%2F+%28x+-+%28-7%29%29+=+%280+-+1%29+%2F+%280+-+%28-7%29%29\"
\n" ); document.write( "\"%28y+-+1%29+%2F+%28x+%2B+7%29+=+-1+%2F+7\"
\n" ); document.write( "Multiply both sides by \"7%2A%28x+%2B+7%29\"
\n" ); document.write( "\"7%2A%28y+-+1%29+=+-%28x+%2B+7%29\"
\n" ); document.write( "\"7y+-+7+=+-x+-+7\"
\n" ); document.write( "\"7y+=+-x\"
\n" ); document.write( "\"y+=+-%281%2F7%29%2Ax\"
\n" ); document.write( "This is of the form \"y+=+mx\", and \"m\" is the slope
\n" ); document.write( "Any line perpendicular to this one will have slope
\n" ); document.write( "\"-%281%2Fm%29\", in this case, \"-%281%2F%28-%281%2F7%29%29%29+=+7\"
\n" ); document.write( "So, the line tangent to the circle at (-7,1) will have
\n" ); document.write( "slope = \"7\".
\n" ); document.write( "\"%28y+-+1%29+%2F+%28x+-+%28-7%29%29+=+7\"
\n" ); document.write( "\"y+-+1+=+7%2A%28x+%2B+7%29\"
\n" ); document.write( "\"y+-+1+=+7x+%2B+49\"
\n" ); document.write( "\"y+=+7x+%2B+50\" answer
\n" ); document.write( "I'll plot the circle and the line
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