document.write( "Question 194785: i have to write an equation of the line that is tangent to the circle at that point:\r
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document.write( "x^2+y^2=50; (-7,1) \n" );
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Algebra.Com's Answer #146117 by josmiceli(19441)![]() ![]() You can put this solution on YOUR website! First, answer the question: \"Is the point (-7,1) \n" ); document.write( "on the circle?\" \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "The center of the circle is the origin. \n" ); document.write( "Next find the equation of the line that \n" ); document.write( "contains the points (0,0) and (-7,1) \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Multiply both sides by \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "This is of the form \n" ); document.write( "Any line perpendicular to this one will have slope \n" ); document.write( " \n" ); document.write( "So, the line tangent to the circle at (-7,1) will have \n" ); document.write( "slope = \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "I'll plot the circle and the line \n" ); document.write( " |