document.write( "Question 194700: A circle has center (p,q) and is tangent to the x-axis. Write the standard equation of the circle. \r
\n" ); document.write( "\n" ); document.write( "I got (x-p)^2 + (y-q)^2 = r^2 but I'm not sure about the radius. Please help to clarify what I would do with r (radius) and why.
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Algebra.Com's Answer #146078 by scott8148(6628)\"\" \"About 
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the circle is tangent to the x-axis
\n" ); document.write( "this means that the distance (in the y direction) from the center to the x-axis is the radius\r
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\n" ); document.write( "\n" ); document.write( "so the y-coordinate of the center (q) is the radius of the circle
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