document.write( "Question 194669: Solve the linear system in the next question using the Substitution Method. Describe the steps.\r
\n" ); document.write( "\n" ); document.write( "2x + 3y = -4
\n" ); document.write( "x – 2y = 5
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Algebra.Com's Answer #146068 by checkley77(12844)\"\" \"About 
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2x + 3y = -4
\n" ); document.write( "x – 2y = 5 or x=2y+5
\n" ); document.write( "now substitute (2y+5) for x in the first equation & solve for y.
\n" ); document.write( "2(2y+5)+3y=-4
\n" ); document.write( "4y+10+3y=-4
\n" ); document.write( "7y=-4-10
\n" ); document.write( "7y=-14
\n" ); document.write( "y=-14/7
\n" ); document.write( "y=-2 ans.
\n" ); document.write( "Now replace y by -2 in the second equation & solve for x.
\n" ); document.write( "x-2(-2)=5
\n" ); document.write( "x+4=5
\n" ); document.write( "x=5-4
\n" ); document.write( "x=1 ans.
\n" ); document.write( "Proof:
\n" ); document.write( "2*1+3*-2=-4
\n" ); document.write( "2-6=-4
\n" ); document.write( "-4=-4
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