document.write( "Question 194686: LS Antifreese contains 74% ethylene glycol. BT oil Antifreeze contains 58% ethylene glycol. How many gallons of each antifreeze must be used to make 10 gallons of antifreeze that is 68% ethylene glycol? \n" ); document.write( "
Algebra.Com's Answer #146066 by checkley77(12844)\"\" \"About 
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.74x+.58(10-x)=.68*10
\n" ); document.write( ".74x+5.8-.58x=6.8
\n" ); document.write( ".16x=6.8-5.8
\n" ); document.write( ".16x=1
\n" ); document.write( "x=1/.16
\n" ); document.write( "x=6.25 gal. of 74% is used.
\n" ); document.write( "10-6.25=3.75 gal. of 58% is used.
\n" ); document.write( "Proof:
\n" ); document.write( ".74*6.25+.58*3.75=.68*10
\n" ); document.write( "4.625+2.175=6.8
\n" ); document.write( "6.8=6.8
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