document.write( "Question 194674This question is from textbook An Introduction to Abstract Algebra with Notes to the Future Teacher
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Algebra.Com's Answer #146065 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
First, perform synthetic division on the polynomial \"z%5E3%2Bi\" using the test zero \"z=i\". Note: you can easily solve for \"z\" and find that one solution is \"z=i\"\r
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document.write( "i |  1  0  0   i\r\n" );
document.write( "  |     i  -1  -i\r\n" );
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document.write( "     1  i  -1   0\r\n" );
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\n" ); document.write( "\n" ); document.write( "Since the first three numbers in the third row are 1, i, and -1, this means that \r
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\n" ); document.write( "\n" ); document.write( "\"z%5E3%2Bi=%28z-i%29%28z%5E2%2Biz-1%29\"\r
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\n" ); document.write( "\n" ); document.write( "Now simply use the quadratic formula to solve \"z%5E2%2Biz-1=0\" for \"z\":\r
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\n" ); document.write( "\n" ); document.write( "\"z+=+%28-b+%2B-+sqrt%28+b%5E2-4ac+%29%29%2F%282a%29\" Start with the quadratic formula\r
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\n" ); document.write( "\n" ); document.write( "\"z+=+%28-%28i%29+%2B-+sqrt%28+%28i%29%5E2-4%281%29%28-1%29+%29%29%2F%282%281%29%29\" Plug in \"a=1\", \"b=i\", and \"c=-1\"\r
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\n" ); document.write( "\n" ); document.write( "\"z+=+%28-i+%2B-+sqrt%28+-1-4%281%29%28-1%29+%29%29%2F%282%281%29%29\" Square \"i\" to get \"i%5E2=%28sqrt%28-1%29%29%5E2=-1\". \r
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\n" ); document.write( "\n" ); document.write( "\"z+=+%28-i+%2B-+sqrt%28+-1%2B4+%29%29%2F%282%29\" Multiply\r
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\n" ); document.write( "\n" ); document.write( "\"z+=+%28-i+%2B-+sqrt%28+3+%29%29%2F%282%29\" Combine like terms.\r
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\n" ); document.write( "\n" ); document.write( "So the other two solutions are \"z+=+%28-i+%2B+sqrt%28+3+%29%29%2F%282%29\" or \"z+=+%28-i+-+sqrt%28+3+%29%29%2F%282%29\"\r
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\n" ); document.write( "\n" ); document.write( "Answer:\r
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\n" ); document.write( "\n" ); document.write( "So the 3 solutions are \"z=i\", \"z+=+%28-i+%2B+sqrt%28+3+%29%29%2F%282%29\", or \"z+=+%28-i+-+sqrt%28+3+%29%29%2F%282%29\"\r
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