document.write( "Question 194589: If the area of the rectangle is 32 square units, find the value of x.\r
\n" ); document.write( "\n" ); document.write( "Length = 8 Width = Square root of 2x-4
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Algebra.Com's Answer #146056 by ankor@dixie-net.com(22740)\"\" \"About 
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If the area of the rectangle is 32 square units, find the value of x.
\n" ); document.write( "Length = 8 Width = Square root of 2x-4
\n" ); document.write( ":
\n" ); document.write( "Length * width = 32
\n" ); document.write( "therefore
\n" ); document.write( "\"8%2Asqrt%282x-4%29\" = 32
\n" ); document.write( "Divide both sides by 8, results: (sorry about this mistake
\n" ); document.write( "\"sqrt%282x-4%29\" = 4
\n" ); document.write( "square both sides, results
\n" ); document.write( "2x - 4 = 16
\n" ); document.write( "2x = 16 + 4
\n" ); document.write( "2x = 20
\n" ); document.write( "x = 10
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\n" ); document.write( ":
\n" ); document.write( "Check solution in original equation:
\n" ); document.write( "\"8%2Asqrt%282%2810%29-4%29\" = 32
\n" ); document.write( "\"8%2Asqrt%2816%29\" = 32
\n" ); document.write( "8* 4 = 32
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