document.write( "Question 194631This question is from textbook
\n" );
document.write( ": Describe the graph of each equation.\r
\n" );
document.write( "\n" );
document.write( "y=1/x\r
\n" );
document.write( "\n" );
document.write( "how would you describe this? I dont understand the answer in my book. \n" );
document.write( "
Algebra.Com's Answer #146020 by RAY100(1637)![]() ![]() ![]() You can put this solution on YOUR website! y =1/x,,,,also called the reciprocal function \n" ); document.write( ", \n" ); document.write( "there is a horizontal asymptote at ,, y=o \n" ); document.write( ", \n" ); document.write( "and a vertical asymptote at x=0 \n" ); document.write( ", \n" ); document.write( "to rough sketch this, draw a standard x - y coordinate system. \n" ); document.write( "sketch in asymptotes, (same as x,y axis) \n" ); document.write( ", \n" ); document.write( "starting at far left, x=- infinity, y is on the negative side of zero( approaches zero), \n" ); document.write( "going to right this function curves downward, to - infinity as x approaches zero. \n" ); document.write( ", \n" ); document.write( "skipping over the x=0 asymptote, The function picks up at + infinity \n" ); document.write( "as we go right it curves down to approach y=0 as x = + infinity \n" ); document.write( ", \n" ); document.write( "in short in the 3rd quadrant it is a \"u\" vertex at (0,0) pointed down and to left, \n" ); document.write( "in the 1st quadrant, it is a \"u\" vertex at (0,0) pointing up and to right. NOTE that the vertex does not touch (0,0) , but only approaches along the 45 degree line, y=x. \n" ); document.write( ", \n" ); document.write( "hpoefully this helps \n" ); document.write( " |