document.write( "Question 194613: Hello!\r
\n" ); document.write( "\n" ); document.write( "Graph the following parabola. Calculate and identify vertex and intercepts in graph. Problem - y=x^2+4x+3\r
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\n" ); document.write( " y= (x+1) (x+3) = Is this correct so far? I'm not sure howto graph this parabola. Can you help me? Thank you!!!\r
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Algebra.Com's Answer #146011 by Mathtut(3670)\"\" \"About 
You can put this solution on YOUR website!
first you have to rewrite this so that the variable y is positive and set this up to complete the square
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\n" ); document.write( "\"y=-1%28x%5E2%2B4x%29-3%29\"
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\n" ); document.write( "\"y=-1%28x%5E2%2B4x%2B4%29%2B4-3\"
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\n" ); document.write( "\"y=-1%28x%2B2%29%5E2%2B1\"
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\n" ); document.write( "vertex is at (-2,1)
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\n" ); document.write( "intercepts are found by setting y to zero
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\n" ); document.write( "we know it opens down because it is in the form \"y=x%5E2\" and coefficient is a negative 1
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\n" ); document.write( "\"0=x%5E2%2B4x%2B3\"--->\"%28x%2B1%29%28x%2B3%29=0\" so x intercepts are -1,-3: (-1,0)(-3,0)
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\n" ); document.write( "\"graph%28300%2C300%2C-10%2C10%2C-10%2C10%2C-x%5E2-4x-3%29\"
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